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DIADEM : DIADEM Is an Acronym for Deadalnix's Edges Method

I invented this method. It looks like BH and M2 method, and is an alternative to thoses. Please let me know any impressions or improvements you find.

Summary :


U face edges

Rf et Lf stickers

Ro et Lo stickers

Ro/Lo et Rf/Lf combinations

DB edge

Summary table

This method is more effective than M2 on numbers of moves and eliminate some ugly cases as well as regrips. It require more moves than BH but is more finger friendly. In this method, edges are solved 2 by 2 by building our own sequences using patterns.

I mention here big cube safe solutions, but also deal with some 3x3x3 specific improvements.

Theoretical notions.

An edge is the entire piece whatever is his orientation. An edge is made of 2 stickers. In memorisation phase, you have to memorize sticker cycles. DF stand for D sticker on edge which is between D and F face. I use FD as buffer. We will use this buffer to solve cycles of stickers on the cube.

This method contains many move sequences, but you don't need to learn them all by heart. They can be deduced by understanding how cases works. If you understand how cases works, you'll be able to find the good move sequence « on the fly ».

To express cases, I have a notation for groups of stikers. All the stickers on a face are xf where x is the face name (f stand for face). For exemple, Rf is the group of all the stickers on R face. All the stikers of an edge that belong to a face, but which isn't on the face is xo (o for orbit). So Ro is the group made by all the stickers of R face edges, which are not on R face (so FR, UR, BR and DR).

[x] is a move of x face. So [R] is R, R' or R2. [x]' is the reverse move. An [x] move as obviously to be in the pattern if theyre is an [x]' move. For exemple, [R]U[R]' can be RUR', R'UR or R2UR2.

Standard set-up are j and k. J and K are set-ups for the same piece, but without messing up the M slice.

{JK} means that you have to execute J then K but with cancelation moves (that can be predicted).

Stickers belong to more than 1 group. They can be handled using pattern for both groups. For exemple RU is an Uo and an Rf.

U face edges.

It's important to master stickers on U face. The following cases can solve any position with a simple [U] as set-up. Obviously, you can use the inverses also. Some case are presented more than once to allow the reader to choose the solution he/she prefers.

Cases begining with an Uo :

Cases begining with an Uf :

Some shortcuts usable on 3x3x3 :

Rf and Lf stickers.

I will deal with Rf stickers. Lf stickers can be handled the same way using symetry. For these stickers, set-up is U[R]U' for J and [R]U' for j. The set-up have to put the sticker on BU.

Solve 2 Rf sticker is simple. Just apply the following pattern : jM2[J'K}M2k'. The solution is 9WTM.

For help understanding, I will explain Rf RD. We deduce j = RU' J = URU' k = R2U' K = UR2U' . So the solution is :

To combine an Rf with an Uo we put the Uo sticker in BU using [U] and apply {[U]J}M2J'M2[U]' or in RU and apply [U]jM2J'M2{[U]'U} (which is basicaly the same). The Lf are solved the same way using symetry.

On 3x3x3, you can use jM'U2M{U2j'} for Rf LU and {jU2}M'U2Mj' for LU Rf, which is 7 WTM.

Use only on 3x3x3 !

To solve Rf and Lf you have to use a commutator with the cube on side. All cases are 9WTM exept LD RD which is 11WTM. I prefer this option to the alternative below.

If you already know M2, here is an alternative which can be interesting for you : with an [L] set-up, you can go to a LU Rf solution that I already presented. The solution will be {jK}M2K'M2j'. You can use the LU tips on 3x3x3.

Use only on 3x3x3 !

Let's see how to handle an Rf with an Uf. To do so, we put the Uf in UF using [U] and we use the following pattern : M2JMJ'M. This is 9 WTM for UF and 11WTM for others Uf.

Ro and Lo stickers.

This part is close to the first one. Don't worry if it looks similar.

You will find in this part the explainations for Ro. Lo can be solved the same way using symetry. For theses stickers, set-ups are U'[R]U for J and [R]U for j. The set-up put the sticker in UF.

To solve 2 Ro, you have to use this pattern : jM'{J'K}Mk'. The solution is 9WTM.

As an exemple i will explain FR DR. We deduce j = RU J = U'RU k = R2U K = U'R2U. So the solution is :

To combine Ro and Uf, you put the Uf sticker in UF with [U] and use JM'J'M' for Ro UF or M'JMJ' for UF Ro wich is 8 WTM for UF and 9 WTM for others Uf. Lo can be deduced by symetry.

To solve Ro and Lo, we use a commutator on side. Solutions are 8 or 10 WTM exept for DR DL which is 12 WTM.

You can improve the solution on 3x3x3 using an RM set-up and a regrip. You souldn't use this unless you are very familiar with the rest of the method.

To solve Ro then Uo, we put the Uo sticker in BU with an [U] move and we use MJM2J'M for Ro BU and M'JM2J'M' for BU Ro. This is 9 WTM for BU or 11 WTM for another Uo.

Ro/Lo and Rf/Lf combinations.

To solve Rf and Lo, we put the cube on side. Then we use a commutator to cycle the pieces. Look at the exemples :

If edges are one the same face, thing can become a little more complex. If they are opposite, then a commutator is easy to find :

If they are adjacent, you can set-up using u or u' if you have UR edge. Othewise, you need to improvise another set-up.

DB edge.

To solve the DB edge, use the pattern M2JM'J'M' for Rf and M'JM'J'M2 for Ro. Ux cases can be solved with [U] set-up.

BD is a little bit more tricky but nothing impossible. With an Rf, use jMU2MU2M2j' and jM2U2M'U2MU2M'U2M'j' on big cubes.

Solution for 3x3x3 cube.

Solution for big cubes.

An alternative solution is to use the followinfg sequence : [R]f'RUM2U'R'UM2U'f[R]'. It works on big cubes.

With an Ro, just regrip using x and you will get a Uo Rf case (with an F/B symetry). You already know how to solve this case.

Summary table.

No explainations here. Just a table with cases and associated pattern.

  Rf Ro Lf Lo   Uf Uo DB BD  
Rf jM2{J'K}M2k' Many solutions, see explainations. z[D]{[U]U'}RUM2U'R'UM2[U]'[D]'z'
Rf [U]M'JM'J'M2[U]' {[U]J}M2J'M2[U]' MJMJ'M2 jM2M2M'U2M'j' (3x3x3)
Ro Many solutions, see explainations. jM'{J'K}Mk' z'[D][U]M'UL'U'MUL{U'[U]'}[D]'z
Ro {[U]J}M'J'M[U]' [U]MJM2J'M[U]' M2JMJ'M Setup vers Uo Rf via x. Ro
Lf z'[D][U]M2URU'M2UR'{U'[U]'}[D]'z
jM2{J'K}M2k' Many solutions, see explainations. Lf [U]M'JM'J'M2[U]' {[U]J}M2J'M2[U]' MJMJ'M2 jM2M2M'U2M'j' (3x3x3)
Lo z'[D][U]M'U'RUM'U'R'{U[U]'}[D]'z
Many solutions, see explainations. jM'{J'K}Mk' Lo {[U]J}M'J'M[U]' [U]MJM2J'M[U]' M2JMJ'M Setup vers Uo Lf via x. Lo